C program to count total number of notes in given amount

 #include <iostream>

using namespace std;

int main()
{
    // 500,100,50,20,10,5,2,1

    int n;

    int count1,count2,count3,count4,count5,count6,count7,count8;
    count1=count2=count3=count4=count5=count6=count7=count8=0;

    cin>>n;

        if(n>=500){
          count1=n/500;

          n=n%500;
        }
        if(n>=100){
            count2=n/100;

            n=n%100;
        }
        if(n>=50){
            count3=n/50;

            n=n%50;
        }
        if(n>=20){
            count4=n/20;

            n=n%20;
        }
        if(n>=10){
            count5=n/10;
            cout<<"10: "<<count5<<endl;
            n=n%10;
        }
        if(n>=5){
            count6=n/5;

            n=n%5;
        }
        if(n>=2){
            count7=n/2;

            n=n%2;
        }
        if(n>=1){
           count8=n/1;

            n=n%1;
        }


        cout<<"500: "<<count1<<endl;
        cout<<"100: "<<count2<<endl;
        cout<<"50: "<<count3<<endl;
        cout<<"20: "<<count4<<endl;
        cout<<"10: "<<count5<<endl;
        cout<<"5: "<<count6<<endl;
        cout<<"2: "<<count7<<endl;
         cout<<"1: "<<count8<<endl;















    return 0;
}